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Engineering

Air compressor

Start a single-cylinder compressor on a ten-litre receiver and watch the gauge climb: each stroke draws air through the intake plate, squeezes it hot and pushes it past the delivery plate once the cylinder beats the tank. The mass delivered per cycle shrinks as the tank fills, close to the clearance-volume closed form 1 - c ((p/p0)^(1/n) - 1); a larger clearance delivers less. At the set pressure the switch stops the motor, the unloader vents the cylinder and the machine coasts to rest; open the consumer and the tank settles where delivery meets the bleed. Motor work and intake enthalpy are booked against the gas’s internal energy, the heat to wall and room and the air sent on.

Air compressor — Actual application image
Actual application image

What happens

A shunt motor drives an 80 mm compressor by a belt; the slider-crank sweeps the cylinder, the intake and delivery plates open linearly over 0.2 bar and pass compressible flow by the Saint-Venant function, the cylinder gas exchanges heat with its wall and the receiver with the room, a consumer bleeds the receiver through an orifice, and a pressure switch stops the motor at the set pressure, whereupon an unloader vents the cylinder. RK4 at 20 µs on angle, speed and the two gas masses and temperatures, with every flow, work and heat booked at the step ends; the delivery per cycle is read against the clearance-volume closed form.

Try this

Watch the receiver fill and the delivery per cycle shrink; compare it with the clearance closed form; let the switch stop the motor and the unloader vent; then open the consumer and find the balance pressure.

The model and its limits

Ideal gas with constant specific heats, plate valves without mass or bounce, a lumped wall temperature, no oil or ring leakage, a straight motor line. Efficiencies are those of this idealized machine.

Equations used in the module
Equations
V(θ) = c·V_s + A·(2r − x(θ)),  G = A·p_u·Ψ(p_d/p_u)/√(R·T_u)
c_v·m·dT/dt = c_p·T_in·G_in − c_p·T·G_out − p·dV/dt + h·(T_w − T) − c_v·T·dm/dt
J·dω/dt = T_s·(1 − ω/ω_0) + (p − p_0)·dV/dθ − T_f − c·ω
η_v = 1 − c·((p_r/p_0)^(1/n) − 1)

Related experiments

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Steam engine mechanism — Actual application image

Engineering

Steam engine mechanism

Open the throttle on a horizontal engine fed with 6 bar air and watch the slide valve lead the piston: the eccentric’s lap and advance are solved so the steam port cracks open by the lead at dead centre and shuts at the chosen cutoff, exactly acos(1 - 2c) of crank angle. Shorten the cutoff and the air expands in the cylinder, less air per joule of work but less work per cycle; load the brake until the mean effective pressure can no longer carry it and the engine stalls; park the crank at dead centre and it will not start. The admitted enthalpy is booked against the exhaust, the wall, the gas’s energy and the indicated work, and the indicated work against the flywheel, the friction and the brake.

Stirling mechanism — Actual application image

Engineering

Stirling mechanism

Spin a beta-type Stirling engine whose hot cap stands at 650 K and whose cold space is kept at 300 K: the displacer moves the air between them, the power piston a quarter turn behind takes the work, and the pressure follows the Schmidt law M R / (Vh/Th + Vc/Tc + Vr/Tr). Read the cycle work against the Schmidt closed form and the heat in and out against Carnot’s efficiency; load the brake until the engine stalls; cool the hot end and watch the work shrink; set both ends to one temperature and the flywheel coasts to a stop. Change the phase angle and find the ninety-odd degrees that give the most work. The gas work is booked against the flywheel, the friction and the brake.